4. Count squares

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4. Count squares


Problem link :- click here


package program;

public class Searching__4
{

	/*
	 	Consider a sample space S consisting of all perfect squares starting from 
	 	1, 4, 9, and so on. You are given a number n, you have to output the number 
	 	of integers less than N is in the sample space S.
	 			n = 9
	 		output = 2
	 		
	 	lets find the square-root the given number 
	 	and the return 1 number less than the square root of the given number
	 */
	
	static int countSquares(int n)
	{
		int ans = (int) Math.sqrt(n)  - 1  ;
		
		return ans;
	}
	
	
	public static void main(String[] args)
	{
		int ans = countSquares(16);
		
		System.out.println(ans);
	}

}

Time complexity :- O(sqrt(n))
Space complexity :- O(1)

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