10. Find a pair with given differences

-

10. Find a pair with given differences


Problem link :- click here


package program;

import java.util.Arrays;

public class Searching__10
{

	/*
	 	Given an array arr[] of size n and a number diff, you need to write a
	 	program to find if there exists a pair of elements in the array whose difference
	 	is diff
	 				arr[] = {5, 20, 3, 2, 5, 80}	diff = 78
	 				output : 1 or true
	 	
	 	Lets sort the array first 
	 	and then take two pointers one at each end of the array
		and check if the difference is found
	 */
	
	static Boolean findPair(int arr[], int n, int diff)
	{
		//sorting the array
		Arrays.sort(arr);
		
		int i, j;
		i = 0;
		j = 1;
		while(j<n)
		{
			int diff1 = Math.abs(arr[i] - arr[j]);
			
			if(diff1 == diff)
				return true;
			else if(diff < diff1)
				i++;
			else
				j++;
		}
		
		return false;
	}
	
	
	public static void main(String[] args)
	{
		int arr[] = {5, 20, 3, 2, 5, 80};
		int diff = 78;
		Boolean ans = findPair(arr, arr.length, diff);
		if(ans)
			System.out.println("Found");
		else
			System.out.println("Not found");
	}

}

Time complexity :- O(log(n))
Space complexity :- O(1)

Comments

Post a Comment

Popular posts from this blog

4.Sort an array of 0's, 1's & 2's.

-
Image
4.Sort an array of 0's, 1's & 2's. Problem link :- click here C code #include<stdio.h> void swap(int *a, int *b) { int temp; temp = *a; *a = *b; *b = temp; } void sort_012(int A[], int n) { int i, j, m; i = 0; j = n-1; m = 0; while(m<=j) { if(A[m] == 0) { swap(&A[i], &A[m]); i++; m++; } else if(A[m] == 1) { m++; } else { swap(&A[j], &A[m]); j--; } } } void main() { int arr[30]; int n, i; printf("Enter the size of the array\n"); scanf("%d",&n); printf("Enter the elements of the array(only 0, 1, or 2)\n"); for(i=0; i<n; i++) scanf("%d",&arr[i]); printf("Given Array\n"); for(i=0; i<n; i++) printf("\t%d",arr[i]); printf("\n...
Read more

1. Reverse

-
Image
1. Reverse the Array.   Problem link :- Reverse the array Algorithm idea :- C code //Reverse the array #include<stdio.h> void rev_arr(int arr[], int start, int end) { int temp; while(start < end) { temp = arr[start]; arr[start] = arr[end]; arr[end] = temp; start++; end--; } } void print_arr(int arr[], int size) { int i; for(i=0; i<size; i++) printf("\t%d",arr[i]); printf("\n"); } void main() { int arr1[30]; int n, i; printf("Enter the size of the array\n"); scanf("%d",&n); printf("Enter the elements of the array\n"); for(i=0; i<n; i++) scanf("%d",&arr1[i]); printf("Array before reversing\n"); print_arr(arr1, n); rev_arr(arr1, 0, n-1); printf("\nArray after reversing\n"); print_arr(arr1, n); } Java code //Reverse the array package programs;...
Read more

3. Height of Binary tree

-
3. Height of Binary tree Problem link :- click here package Binary_Tree; public class BinaryTree__3 { static int heightOfTree(Node root) { if(root == null) return 0; int left_height = heightOfTree(root.left); int right_height = heightOfTree(root.right); return Math.max(left_height, right_height) + 1; } public static void main(String[] args) { BinaryTree tree = new BinaryTree(); int arr[] = {2, -1, 3, -1, -1, 3}; tree.root = tree.createTree(arr, 0); int ans = heightOfTree(tree.root); System.out.println("Height : " + ans); } } Time complexity :- O(n) Space complexity :- O(n)
Read more